Exercise

The cost of 2 rings and 4 bangles is Rs. 2,54,550. What would be the cost of 6 rings and 12 bangles ?

Let the CP of one ring = Rs. x

and that of one bangle = Rs.y

According to the question,

2x + 4y = Rs. 254550

Multiplying both sides by 3,

6x + 12y = 3 x 254550

= Rs. 763650

If the fractions 2/3, 5/7, 1/6, 3/8, 5/11, 2/7 and 3/5 are arranged in ascending order of their values, which fractions will be the fifth ?

3/5

If amount of Rs. 7,698 is equally distributed amongst 75' ueople, how much approximate amount would each person get ?

Amount received by each person = Rs. (7698/75)

= Rs. 102.64 = Rs. 103

A, B, C, D and E are consecutive even numbers respectively. The average of 5 numbers is 82. What is the product of C and E ?

x + x + 1 + x + 2 + x + 3 + x + 4 = 5 x 82

= 5x + 10 = 410 = 5x = 400

= x = 400/5 = 80 ∴ A = 80

C = 82 and E = 84

= C x E = 82 x 84 = 6383

96% of a number is 19584. What is 56% of that number ?

Let the number be x.

According to the question.

96% of x = 19584

= x = 1958 x 100/96 = 20400

∴ 56% of 20400

= 20400 x 56/100 = 11424

Out of 820 employees in an organisation 20% of the employees got promoted to a higher grade. How many employees did not get promoted ?

Number of employees not

promoted = 80% of 820

= 820 x 80/100 = 656

Deepa invested an amount of Rs. 9,450 at the rate of 5 p.c.p.a. for 3 years. What approximate amount of compound interest will she obtain at the end of 3 years ?

Rs. 1,490

The average age of a lady and her daughter is 28.5 years. The ratio of their ages is 14 : 5 respectively. What is the daughter's age ?

Let the ages of woman and her daughter be 14x and 5x years respectively.

14x + 5x = 28.5 x 2

= 19x = 57 = x = 57/19 = 3

∴ Daughter's age = 5 x 3

= 15 years

Smita invests Rs. 1,87,000, which is 25% of her annual income in the stock market. What is Smitha's approximate monthly income ?

Let smita's annual income be Rs. x

25% of x = 187000

= x x 1/4 = 187000

= x = 187000 x 4 = 748000

∴ Smita's monthly income

= 748000/12 = Rs. 62333

The product of two consecutive odd numbers is 4623. What is the product of the next two consecutive odd numbers ?

√4623 = 67

67 x 69 = 4623

∴ Required product

= 71 x 73 = 5183